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Finding Gamma by Experiment

In this animation, I show two views of of light propagating along the +x direction from
a source for a nominal time t. One view is seen by a viewer, A, where
he/she is moving at +v in the +x direction and the other view of the same propagation
is seen by a viewer, B, that is moving at -v with respect to the source.
Since light travels at speed c in any frame,
the equations for the two viewers are similar but the times in the two viewers'
frames may be different, we have the following transformation equations for
viewers A and B:

where the expansion factor gamma, which is the only difference between the
Galilean and Lorentz transformations, must be computed.
Multiplying equation A by equation B we easily find that

Note that when we substitute the result for `t_A` from equation A1 into equation B1,
we obtain `ct_B=ct_B` as we should expect. Also note that `gamma=1` will not work unless v=0.
What is the difference `t_B-t_A`?

This results in a certain symmetry with respect to `t_0` beween `t_A` and `t_B`.

So how will this experiment be carried out?.
We will need a pulsed light source that is stationary as well as two space
ships to observe the pulse from the source.
The space ships must fly along routes parallel to the x axis and displaced
from it by a small distance so as not to block the light.
The space along the x axis must contain some very fine space dust that will scatter
a small fraction of the light from the light pulse so that it can be seen
by the space ships.
You might comment that this would be an expensive experiment but you must realize that
it is just a way to visualize the effect of `gamma` on the light pulses.
After pulse B has gone 800 units, the results of gamma
for both pulse B and pulse A are stated and they agree with the definition of gamma.